Question

determinati inaltimea[ CF] a unui triunghiABC cu AB=10 cm si aria lui ABC=40 cm patrati

Answer 1

   
[tex]\displaystyle \\ A_{_{\Delta ABC}} = \frac{AB \times CF}{2} \\ \\ CF = \frac{2 \times A_{_{\Delta ABC}}}{AB}= \frac{2 \times 40}{10}= \frac{80}{10}= \boxed{8 ~cm}[/tex]