Question

Determinati lungimile laturilor unui triunghi dreptunghic si isoscel cu aria 128 cm.Dau coroana

Answer 1

h = B /2  ; =>  B = 2h
A = B*h /2
128 = 2h *h /2
2h^2 =256
h^2 =256:2 =128
h =11.31 cm ( AD = h = inaltimea triungh.)

B =2h
B =2*11.31 =22.62  cm (B =  baza triungh  = ipotenuza  BC)
  (B/2 =11.31)
AB^2 = AD^2+BD^2
AB^2 =11.31^2+11.31^2
AB^2 =127.91+127.91 =255.82
AB = 16 cm

AC^2 =BC^2 -AB^2
AC^2 =22.62^2-16^2
AC^2 =511.66 -256 =255.66
AC =16 cm   (AB = AC = 16 cm)