Question

determinati masa de acid clorhidric necesara pentru interactiunea cu 15 mol de hidroxid de magneziu.

Answer 1

2 HCl + Mg(OH)2 = MgCl2 + 2 H2O
2*36.5 g acid..............1 mol hidroxid
x g acid......................15 moli hidroxid 
x = 1095 g acid => masa acid = 1095 g 

Answer 2

MHCl=AH+ACl=1+35.5=36.5g/mol
Mg(OH)2 + 2HCl ---> MgCl2 + 2H2O
1mol Mg(OH)2.....2mol HCl
15mol.................x=30mol
n=m/M=>m=30*36.5=1095g HCl