Question

determinati masa de soda caustica care poate fi neutralizata folosind 150 g desolutie acida cu partea de masa a acidului sulfuric de 9,8%

Answer 1

Cp=md/ms*100==>md=Cp*ms/100=150*9.8/100=14.7g H2SO4
2NaOH + H2SO4 ---> Na2SO4 + 2H2O
80g NaOH.......98g H2SO4
x=12g..................14.7g
MH2SO4=98g/mol
MNaOH=40g/mol

Answer 2

Soda caustica este hidroxidul de sodiu.
2 NaOH + H2SO4 = Na2SO4 + 2 H2O
c = md/ms*100 => md = 9.8*150/100 = 14.7 g acid
2*40 g hidroxid............98 g acid 
x g hidroxid................14.7 g acid
x = 12 g hidroxid
Solutia de acid 9.8% poate neutraliza 12 g soda