Question

determinati masa sarii obtinute in urma reactiei dintre 300 g oxid de cupru cu acidul sulfuric

Answer 1

$\frac{CuO}{300}$ + $\frac{H _{2}SO _{4} }{x}$ ---> $H_{2} O$ + $CuSO _{4}$

$M_{H _{2}SO _{4} } = 2A _{H} + A _{S} + 4A _{O} = 2 +32 + 64 = 98 grame H2SO4$

$M _{CuO} = A _{Cu} + A _{O} = 64 + 16 = 80 grame CuO$

$\frac{64}{300} = \frac{98}{x} =\ \textgreater \ x = \frac{300 X 98}{64} =\ \textgreater \ x = \frac{29400}{64} =\ \textgreater \ x = 459,375$

Deci masa sarii obtinute este 459,375


Nu stiu daca este 100% corect, dar sper ca te-am ajutat :)