Question

Determinati media aritmetica a numerelor $\frac{1}{2} ,$ , 0,(3) si 0,1(6) .

Answer 1

 

$\displaystyle\bf\\\textbf{Transformam numerele zecimale in fractii.}\\\\0,\!(3)=\frac{3}{9}=\frac{1}{3}\\\\0,\!1(6)=\frac{16-1}{90}=\frac{15}{90}=\frac{1}{6}\\\\m_a=\frac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}}{3}=\frac{\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}}{3}=\frac{\dfrac{3+2+1}{6}}{3}=\frac{\dfrac{6}{6}}{3}=\boxed{\bf\frac{1}{3}}$

 

 

Answer 2

Răspuns:

Ma = 1/3

Explicație pas cu pas:

aducem numerele la aceeasi forma

0.(3) = 3/9 = 1/3

0.1(6) = (16-1)/90 = 15/90 = 1/6

Ma = (1/2 + 1/3 + 1/6)/3

= [(3+2+1)/6]/3

= (6/6)/3

= 1/3