Question

Determinati multimea A={x/x∈N,(3x+2):(x-2)∈N

Answer 1

vezi [tex] \frac{3x+2}{x-2} = \frac{3x-6+6+2}{x-2} = \frac{3(x-2)+8}{x-2}=3+ \frac{8}{x-2} x-2 \neq 0 x \neq 2 (numitorii f \neq 0) x-2 divizor a lui 8 x-2=1 x=3 x-2=2 x=4 x-2=4 x=6 x-2=8 x=10 elementele mulțimii 3 4 6 10[/tex]