Question

Determinati n ∈ IN* care verifica inegalitatile : 4 pe 3 < n pe 6 < 17 pe 9

Answer 1

4/3<n/6<17/9
4/3<n/6
24<3n
-3n<-24      (-1) 
n>24/3
n>8

n/6<17/9
9n<17x6
9n<102
n<102/9
n<34/3
⇒n∈(8,+α)

Answer 2

$\frac{4}{3}$<$\frac{n}{6}$<17/9
$\frac{4}{3}$<$\frac{n}{6}$
24<3n
-3n<-24     
n>$\frac{24}{3}$
n>8

$\frac{n}{6}$<$\frac{17}{9}$
9n<17·6
9n<102
n<$\frac{102}{9}$
n<$\frac{34}{3}$

$\frac{34}{3}$=11,(3)

⇒n∈{9,10,11}