determinati nr.a,b,c invers proportionale cu 2,3,4,iar a+b+c=130
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2×a=3×b=4×c=k =>a=k/2
b=k/3
c=k/4
k/2+k/3+k/4=130/1
6×k/2×6+4×k/4×3+3×k/4×3=130×12/12×1
6k/12+4k/12+3k/12=1560/12 }×12
6k+4k+3k=1560
13k=1560
k=1560/13
Apoi inlocuiesti .
b=k/3
c=k/4
k/2+k/3+k/4=130/1
6×k/2×6+4×k/4×3+3×k/4×3=130×12/12×1
6k/12+4k/12+3k/12=1560/12 }×12
6k+4k+3k=1560
13k=1560
k=1560/13
Apoi inlocuiesti .
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