Question

determinați nr a și b știind că a /11 =b/8; 3a +b= 41

Answer 1

a/11 = b/8 => 8×a = 11×b => b = 8a/11
3a+b = 41
inlocuim pe b cu 8a/11
3a+8a/11 = 41 (aducem la acelasi numitor)
(3a×11+8a)/11 = 41
(33a+8a)/11 = 41
41a/11 = 41
41a=11×41 |:41
a = 11

b = 8×11/11
b = 8

Verificare:
11/11 = 8/8 => 1 = 1
3×11+8 = 33+8 = 41

a = 11
b = 8

Answer 2

a/11=b/8
3a+b=41
------------
a=?b=?

a/11=3a:3... =>3a=11*3.....=>3a=33......=>a=33:3.....=>...a=11
b/8=41-3a...=>b=41-11*3..=>b=41-33...=>.....b=8

a/11=11/11=1
b/8  =8/8   =1

a/11=b/8...=> 11/11 = 8/8...=> 1=1