Question

determinati nr de forma abc stiind ca: abc0+2abc+1abc=4476

Answer 1

abc0
2abc
1abc
-------
4476

a+2+1=4 => a+3=4 => a=1
b+a+a=4=> b+2a=4 => b+ 2=4 => b=2
c+b+b=7 => c+2b=7 => c+4=7 => c=3
0+c=c=6 => 2c=6 => 2*3= 6

a=1
b=2
c=3

abc= 123

1230+2123+1123= 4476 (adevarat)