Question

determinati nr de forma abc stiind ca impartite la bc dau catul 6 si restul5

Answer 1

fie bc numar
6*bc+5=100a+bcnumar
5*bc numar=100a-5
pt a=1
5*bc=95 ;
bc numar=19
deci abc numar=119

pt a=2
5*bcnumar=195
bcnumar=39
 deci abc numar=239

pta=3
5*bcnumar=295
bcnumar=59
deci abc numar=359


pt. a=4
5*bc numar=395
bcnumar=79
abcnumar=479

pt a=5
5*bc numar=495
bc numar=99
abcnumar=599

deci abc ∈{119;239;359;479;599}