Question

Determinati nr de moli existenti in a) 4g Dioxid de Carbon b) 25g Carbonat de Calciu c) 320g trioxid sulf d) 64g acid azotic ! VA ROG

Answer 1

mCO2=4 g
n=? 
MCO2=12+2*16=44
n=m/M=4g/44g/mol=0.09 mol
mCaCO3=25 g
n=?
MCaCO340+12+3*16=100 
n=m/M=25g/100g/mol=0,25 moli
c) mSO3=320 g
n=?
MSO3=32+3*16=80
n=m/M=320g:80g/mol=4moli
d) mHNO3=64g

n=?
MHNO3=1+14+3*16=63
n=m/M=64g/63g/mol=1,01 moli