Question

Determinati nr nat n pt. care:

a) n+1 bara n+5

b) n+2 bara n+6

Answer 1

Presupun ca bara inseamna divide .
n + 1 | n + 5
n + 1 | n +1
________(-)
n+1 | 4 => n + 1 apartine divizorilor nr 4
Scadem 1
n apartine multimii { 1 - 1 , 2 -1 , 4-1} =>
n apartine multimii { 0 , 1 , 3 }

n+2|n+6
n+2|n+2
________(-)
n+2| 4
n + 2 apartine multimii divizorilor lui 4 { 1 , 2 , 4}
n apartine multimii { 0 , 2 }