Question

determinati nr natural x din xgalitatatea x intregi 2 supra3 plus 1 intreg x supra 9 = 5

Answer 1

x intregi 2/3=3x+2 supra 3
1 intreg x/9=(1·9+x)/9
(3x+2)/3+(9+x)/9=5 l amplific cu 3 prima fractie si pe 5 si obtin:
3(3x+2)+9+x=9·5
9x+6+9+x=45
9x+x=45-9-6
10x=30
x=30:10
x=3