Question

Determinați nr naturale a<b<c care îndeplinesc simultan condițiile:a+2b+3c=98. 3a+2b+c=94

Answer 1

a<b<c....=> 1*2*3=6....=>98:6=16 rest 2....=>b=16...;a=b-1....c=b+1

a=15
b=16
c=17

a+2b+3c=98
15+16*2+17*3=98......( =>15+32+51=98)

3a+2b+c=96
15*3+16*2+17=94......(=>45+32+17=94)