Question

Determinati nr. naturale n pentru care:
a) n+2 | n+6
b) n+2 | 3n+14

Answer 1

n+2|n+2+4

 n+2|4

n+2∈D4= {1;2;4} n∈N
n+2=1, n∉N
n+2=2, n=0
n+2=4 n=2
 S= {0;2}

n+2|3n+6+8
n+2|3(n+2)+8
 n+2|8
n+2∈D8= {1;2;4;8} n∈N
 n∈{0;2;6}