Question

determinati nr prime a si b stiind ca 3a+16b=54

Answer 1

$3a+16b=54 \\ 3a=54-16b \\ 3a=2(27-8b) \\ (3,2)=1 \Rightarrow 2 | a \Rightarrow a=2. \\ \\ 3a+16b+54 \Leftrightarrow 3 \cdot 2 +16b=54 \Leftrightarrow6+16b=54 \Leftrightarrow 16b=48 \Rightarrow b=3. \\ \\ Solutie:~a=2~si~b =3.$