Question

Determinati nr real m, stiind ca punctul A(2,-3) apartine graficului f : R->R , f(x)= $x^{2}$ - (2m + 1)x +3

Answer 1

f(x)=x²-2mx+x+3
A(2,-3)∈Gf⇔f(2)=-3
f(2)=2²-2*2*m+2+3
-3=4-4m+2+3
-3=9-4m
-12=-4m
m=-12/-4
m=3
Sper ca te-am ajutat