Question

Determinati nr reale pt care:
a)
$(x - 1) \sqrt{2} = y \: + 2$
b)
$x \sqrt{3} - y = 2 \sqrt{3} \: - 1$

Answer 1

a)
$(x - 1) \sqrt{2} = 2$
$x - 1 = \frac{2}{ \sqrt{2} }$
$x = \sqrt{2} - 1$
$y = 0$
b)
$x = 2 \\ y = 1$