Question

determinati nr. reale x si y stiind ca x patrat plus y patrat minus 6radical din 3x plus 4 radical din 5y plus 47 egal cu 0

Answer 1

x²+y²-6√3x+4√5y+47=0
47=27+20
27=(3√3)²
20=(2√5)²
[x²-6√3x+(3√3)²]+[y²+4√5y+(2√5)²]=0
(x-3√3)²+(y+2√5)²=0
x=3√3
y=-2√5