Question

determinati nr. x care verifica egalitatle:
f)0.07:x=0.0007
g)9371.2:x=187.424
h)0.2•x+3.8=4.32
i)1.2•x+3.8=12.56.


va roggg !!!!

Answer 1

f)0.07:x=0.0007
x=0.07:0.0007=100

g)9371.2:x=187.424
x=9371.2:187.424=50

h)0.2•x+3.8=4.32
0.2•x=4.32-3.8
0.2x=0.52
x=0.52:0.2=2,6

i)1.2•x+3.8=12.56
1.2•x+3.8=12.56
1.2x=12.56-3.8
1.2x=8.76
x=8.76:1.2
x=7.3