Question

determinați nr x,y, si z, stiind ca x/2=y/3=z/7 si x×y×z=336

Answer 1

Răspuns

X/2=Y/3=Z/7 = k

X/2= k -> x= 2k

Y/3=k -> y = 3k

Z/7=k -> z= 7k

2k × 3k × 7k = 336

42k = 336

K = 336/42

K = 8

X=16

Y=24

Z= 48