Question

determinati nr x,y,z stiind ca sunt d. p. cu 3/2, 1/3 si 1/5 si x,y,z=100

Answer 1

x/3/2=y/1/3=z/1/5=k
x:3/2=y:1/3=z:1/5=k 
2x/3=y/3=x/5=k
2x/3=k=>x=3k/2
y/3=k=>y=k/3
z/5=k=>z=k/5
x+y+z=100
3k/2+k/3+k/5=100   numitorul comun este 30
15×3k/30+10k/30+6k/30=100
45k/30+10k/30+6k/30=100
61k/30=100=>61k=30×100=>61k=3000=>k=3000/61
daca 
k=3000/61si x=3k/2=>x=3×3000/2×61=>x=3×1500/61=4500/61
k=3000/61 si y=k/3=>y=3000/61×1/3=>y=1000/61
k=3000/61 si z=k/5=>z=3000/61×1/5=>z=600/61

ciudat...daca nu te ajuta da abuz ca nu ma supar