Question

Determinati nr. x,y,z, stiind ca sunt invers proportionale cu nr. 0,5; 0,(3); 0,25
si ca x+y+z=36.

Answer 1

0,5x=0,(3)y=0,25z
x/2=y/3=z/4
y=3x/2
z=4x/2=2x
x+y+z=36
x+3x/2+2x=36
2x+3x+4x=72
9x=72
x=8
y=3×8/2=12
z=2×8=16