Question

Determinati numarul a din egalitatea: 360:8+9-{4+[66:3-5x(306:3-2xa)+16]:4}=43




Va rog!!Dau coroana

Answer 1

45+9-{4+[22-5*(102-2a)+16]:4} = 43

54-{4+[22-5*(102-2a)+16]:4} = 43

4+[22-5*(102-2a)+16]:4=54-43

4+[22-5*(102-2a)+16]:4= 11

4+[22-5*(102-2a)+16]=44

22-5*(102-2a)+16 = 40

22-5*(102-2a)= 24

5*(102-2a) = -2

102-2a = -2/5

2a = 102+2/5 amplifici pe 102 cu 5

2a = 512/5

a=  512/5*1/2

a = 256/5