Question

determinati numarul abc care impartit la 5 da catul bc si
restul a

Answer 1

abc:5=b rest a

abc+a=numărul abc
(abc+a):5=[(bc+a)×5]+a
(4a×5):5=a
a=(4×5):5
a=20:5
a=4

(4bc+4):5=[(bc+4)×5]+4
(2×5):2=c
c=10:2
c=5

(4b5+4):5=[(b5+4)×5]+4
4b9:5=(b9×5)+4
b=a+c
b=4+5
b=9

(495+4):5=[(95+4)×5]+4
499:5=(99×5)+4
499:5=495+4
499=499

numărul abc=499

Verificare:
abc:5=b rest a
499:5=99 rest 4
abc=99×5+4
abc=495+4
abc=499