Question

Determinati numarul de moli existenti in 320 g SO3

a. Cate grame reprezinta 0,04 kmoli - H2SO4
b. Calculeaza compozitia procentual a substantei oxidului de mangan

Answer 1

320 g SO3     MSO3=32+3.16=80
?moli SO3      80 g SO3---------1mol SO3
                         320g SO3------X moli SO3
                        X=320:80=4 moliSO3




0,04 k moli H2SO4            MH2SO4=2+32+4.16=98
? g H2SO4                        98kg H2SO4-----1kmol H2SO4
                                           ykgH2SO4-------0,04 kmoli H2SO4
                                        y=98.0,04=3,92 kg H2SO4=3920 gH2SO4


Compoz. proc.           MMnO=55+16=71
MnO                           71 g MnO-------55gMn-------16 g O
                                   100gMnO------ a-----------------b
                               a=100.55:71=77,4 la suta Mn
                                b=100.16:71=22,53 la suta O
a MnO