Question

Determinați numărul de moli existenți in:
a)4 g CO2
b)25g CaCO 3
c)320 g SO 3
d)63 g HNO 3

Answer 1

4a)4 g C02
m=nxM
M (indice)CO2=12+16x2
=12+32
=44g/mol
1 mol CO2=44g/mol
n=4g:44g/mol
n=11moli CO2
b)25gCaCO3
m=nxM
M(indice)CaCO3=40+12+16x3
=100g/ mol
1 mol CaCO3= 100g/ mol
n= 25g:100g/mol=4moliCaCO3
c)320gSO3
m= nxM
M( indice) SO3=80g/mol
1mol SO3=80g/mol
n=320g:80g/mol=4 moliSO3
d)63gHNO3
m= nxM
M( indice)HNO3= 1+14+16x3
=720g/mol
1 molHNO3=720g/mol
n=63g:720g/mol=0.0875