Question

• Determinati numărul de moli existenti in:
a) 4 g CO2
b)25g CaCO3
c)320g SO3
d)63g HNO3
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Answer 1

$n = \frac{m}{mm}$

n=numar de moli

m=masa

mm=masa moleculara

a)mCO2=4 G

MCO2=12 + 32 = 44g

n=m/M=4/44=1/11 =0.09 moli

b)mCaCO3= 25 g

MCaCO3= 40 + 12 + 48= 100

n=m/M=25/100=1/4= 0.25 moli

c)mSO3=320 g

MSO3=32+48=80 g

n=m/M=320/80=4 moli

d)mHNO3=63 G

MHNO3=1+14+48=63 g

n=m/M=63/63=1 mol