Question

Determinati numărul de solutii intregi ale ecuației 3x^2 + 8x - 3 = 0.
​

Answer 1

$</u><u>(</u><u>x - 3 ) ( 3 x + 1 ) = 0(X-3)(3X+1)=0</u></p><ol><li><u>x - 3 ) ( 3 x + 1 ) = 0(X-3)(3X+1)=0 \\ x = 3 \\ x = - \frac{1}{3} \\ 3x + 1 = 0 \\ x = 3 \: si </u><u>- \frac{1}{3} </u></li><li></li><li><u>(</u><u>x - 3 ) ( 3 x + 1 ) = 0(X-3)(3X+1)=0 \\ x = 3 \\ x = - \frac{1}{3} \\ 3x + 1 = 0 \\ x = 3 \: si </u><u> - \frac{1}{3}$

Succes:))

Answer 2

a=3, b=8, c=-3

Δ=b²-4ac=8²-4*3*(-3)=64+36=100

x1=(-b+√Δ)/2a=(-8+10)/(2*3)=2/(2*3)=1/3

x2=(-b-√Δ)/2a=(-8-10)/(2*3)=-18/(2*3)=-18/6=-3∈Z

S={-3}