Question

Determinați numărul n ,astfel încât:
(0,2)la puterea 2N+1=0,00032
Va rog

Answer 1

0,2^(2n+1) = 0,00032 
0,2^(2n+1) = 0,2^5
2n+1 = 5 
2n = 5-1 
2n = 4 
n = 4:2
n = 2 

Answer 2

[tex]\it 0,2^{2n+1} =0,00032 \Rightarrow \left(\dfrac{2}{10}\right)^{2n+1} =\dfrac{32}{100000} \Rightarrow \left(\dfrac{2}{10}\right)^{2n+1} =\dfrac{2^5}{10^5} \\\;\\ \\\;\\ \left(\dfrac{2}{10}\right)^{2n+1} =\left(\dfrac{2}{10}\right)^5 \Rightarrow 2n+1=5 \Rightarrow 2n = 4 \Rightarrow n = 2[/tex]