Question

Determinati numarul natural abc care impartit la 5 da catul bc si restul a

Answer 1

Răspuns:

abc:5= bc rest a

=> abc+a=nr. abc

=> (abc+a):5=[(bc+a)×5]+a

=>(4a*5):5=a

 a=(4*5):5

 a=20:5

 a=4

=>(4bc+4):5=((bc+4)*5)+4

=>(2*5):2=c

 c=10:2

 c=5

=>(4b5+4):5)=((b5+4)*5)+4

=>b=a+c

=>b=4+5

 b=9

=>(495+4):5=((95+4)*5)+4

=>499:5=99*5+4

=>499:5=495+4

=>499=499

numarul abc=499

abc:5=bc rest a

499:5=99 rest 4

abc=495+4

abc=499

SUCCES!