Question

Determinati numarul natural de 3 cifre de forma : abc stiind ca abc= ab+bc+ca , a diferit de 0.

Answer 1

abc = ab +bc+ca

abc = 10a + b + 10b + c + 10 c + a

100 a + 10 b + c = 10a + b + 10b + c + 10 c + a

100 a - 11a = 10 b - 10b + c - c + b + 10 c

89 a = 10c + b => 89a = cb => a = 1 => c = 8, b = 9. abc = 198