Question

Determinati numarul natural de forma abcdef stiind ca: def: abc= 6 rest 72, iar 6768: ( def- abc) -3x2+0:5=3

Answer 1

6768:(def-abc)-3x2+0:5=3,pt a lucra usor notam (def-abc)=A
6768:A-3x2+0:5=3
6768:A-6+0=3
6768:A-6=3
6768:A=9
A=6768:9=752
def-abc=752⇒def=abc+752
mai stim ca def:abc=6rest72,atunci (def-72):abc=6
inlocuim pe def din prima expresie,si avem (abc+752-72):abc=6
(abc+681):abc=6
(abc+680)=6xabc
6xabc-abc=680
5xabc=680
abc=680:5=136
def-abc=752
def=752+abc
def=752+136=888
numarul abcdef  este136888