Question

DETERMINATI NUMARUL NATURAL N SINCA : 2^3XN+1=2 ^46 (PS ^INSEAMNA LA PUTERE 3 SI UNDE SCRIE XN+1 ESTE TOT RIDICAT LA PUTERE )

Answer 1

2^3×n+1=2 ^46
2^3n+1=2^46
3n+1=46
3n=45
n=15

Answer 2

2³ⁿ⁺¹=2⁴⁶ ⇔
3n+1=46 ⇔
3n=45 ⇔
n=15