Question

Determinati numarul natural n stiind ca : 2^n+3 + 2^n+1 + 2 ⁿ= 88

Answer 1

$2^{n+3}+ 2^{n+1}+2^n=2^n*2^3+2^n*2+2^n=2^n(2^3+2+1)=2^n*11$

$2^n*11=88$
$2^n=88:11=8$
$2^n=2^3$
$n=3$

Answer 2

2 ∧n + 2³+2∧n+2+2∧n=88
2∧n(2³+2+1)=88
2∧n(8+2+1)=88
2∧n·11=88
2∧n=88÷11
2∧n=8
,⇒n=3