Question

Determinati numărul natural n stiind că: 2^n+3+2^n+1+2^n= 88

Answer 1

Explicație pas cu pas:

${2}^{n + 3} + {2}^{n + 1} + {2}^{n} = 88$

${2}^{n} \cdot ({2}^{3} + 2 + 1) = 88$

${2}^{n} \cdot (8 + 2 + 1) = 88$

${2}^{n} \cdot 11 = 88 \iff {2}^{n} = 8$

${2}^{n} = {2}^{3} \implies \bf n = 3$