Question

Determinati numarul natural n stiind ca 2 ^n+3+2^n+1+2^n=88

Answer 1

[tex]2^{n+3}+2^{n+1}+2^n=88\\ 2^n*2^3+2^n*2+2^n=88\\ 2^n(2^3+2+1)=88\\ 2^n*11=88\\ 2^n=8\\ 2^n=2^3=\ \textgreater \ n=3[/tex]