Question

determinati numarul natural x ,astfel incat : 2 la n +1 supra 9 = 8 supra 3n

Answer 1

[tex] \frac{2 ^{n+1} }{9} = \frac{8}{3n} =\ \textgreater \ 2^{n+1} *3n=72 [/tex]
$72= 2^{3} * 3^{2}$
$2^{n+1} = 2^{3} =\ \textgreater \ n+1=3=\ \textgreater \ n=2$
$3n= 3^{2} =\ \textgreater \ 3n=9=\ \textgreater \ n=3$

Answer 2

2 la n +1 supra 9 = 8 supra 3n

[tex]\it 2^n+\dfrac{1}{9} =\dfrac{8}{3}n \Rightarrow 9\cdot 2^n +1 = 24n \Rightarrow S = \O [/tex]


(9·2^n +1 = impar,  24n = par )