Question

Determinati numarul natural x daca : a) x supta 72 = 2 supra 9 b) 3 supra 5=12 supra 3x + 1 ( Imediat va roog )

Answer 1

 $a) \frac{x}{72}= \frac{2}{9} \\ \\ x= \frac{2*72}{9}=16 \\ \\ x=16 \\ \\ \\ \\b) \frac{3}{5}= \frac{12}{3x+1} \\ \\ 3(3x+1)=12*5 \\ \\ 9x+3=60 \\ \\ 9x=60-3 \\ \\ 9x=57 \\ \\ x= \frac{57}{9}$

Answer 2

a) x÷72=2÷9=> x×9=72×2=> x=16
b)3÷5=12÷3×x+1=>(3×x+1)×3=5×12=>
=>9×x+3=60=>20=3×x+1=>19=3×x=>
=>x=19÷3