Question

Determinați numărul natural x din egalitate : {[(x-8)×7+6-5]-4}×3-2=10.​

Answer 1

{[(x-8)×7+1]-4}×3-2=10

{[(x-8)×7+1]-4}×3=10+2

{[(x-8)×7+1]-4}×3=12

[(x-8)×7+1]-4=12÷3

[(x-8)×7+1]-4=4

(x-8)×7+1=4+4

(x-8)×7+1=8

(x-8)×7=8-1

(x-8)×7=7

x-8=7÷7

x-8=1

x=1+8

x=9