Question

determinati numarul natural x pt care au loc egalitatile:121 in baza 3=x in baza 4:    

34 inbaza5=x in baza 2: 

     
110011 in baza 2=x in baza 10: 

  
1210 in baza 4=x in baza 3

Answer 1

121 in baza 3=1+3+9=13 in baza 10=31 inbaza 4 =(3*4+1)

34 in baza 5=4+3*5=19 in baza 10=16+2+1=10011 in baza 2

110011 in baza 2=1+2+16+32=51 in baza 10


asta e mai greu
1210 in baza 4=0+1*4+2*16+1*64=36+64=100 in baza 10
100 in baza 10=81+2*9+1*1=3^4+0*3³+2*3²+0*3+1*3^0=10201 in baza 3