Question

Determinati numarul real m pentru care varful parabolei asociate functiei f:R->R,f(x)=-x patrat+3mx+1 are abscisa egala cu 3/2

Answer 1

Varful parabolei este

$x_V=-\dfrac{b}{2a}=-\dfrac{3m}{2}$

Deci

$-\dfrac{3m}{2}=\dfrac32\Rightarrow m=-1$

Answer 2

Functia de gradul 2 are forma: f(x)=$a*x^{2} + b*x+c$
In acest caz: a=-1; b=3m; c=1
Astfel, notam cu V varful parabolei, iar $x_{V}=- \frac{b}{2a}= \frac{3m}{2} = \frac{3}{2}=> m=1$