Question

Determinati numere prime a,b,c stiind ca 6a +2b +9c = 99.
Va rog ajutati-ma !!

Answer 1

6a +2b +9c = 99
6a=99-2b-9c
6a:6=99:6-2b:6-9c:6
$a= \frac{99}{6} - \frac{2}{6}b- \frac{9}{6}c$
$a= \frac{33}{2} - \frac{1}{3}b- \frac{3}{2}c$, b∈R, c∈R