Question

Determinati numerele : a,b,c invers proportionale cu 2,4,8 stiind ca a + b + c = 14 URGENT !!!!

Answer 1

a b c
2 4 8

a*2=b*4=c*8=t
a*2=t
a=$\frac{t}{2}$
b*4=t
b=t/4

c*8=t
c=t/8

a+b+c=14
t/2+t/4+t/8=14
Aducem la același numitor,numitorul comun fiind 8
4t+2t+t=112
7t=112
t=16
a=16/2 
a=8

b=16/4
b=4

c=16/8
c=2

Answer 2

{a, b, c} i.p {2, 4, 8}=>2a=4b=8c=k
2a=k=>a=k/2
4b=k=>b=k/4
8c=k=>c=k/8
a+b+c=14
k/2+k/4+k/8=14
N.C=8
4k+2k+k=112
k (4+2+1)=112
k*7=112
k=112/7
k=16=>
a=16/2=8
b=16/4=4
c=16/8=2