Question

Determinati numerele a,b,c si d direct proportionale cu 0,2;0,5;0,(3) si 0,(6), stiind ca 3a-c+d-b=13

Answer 1

a=0,2k=k/5
b=0,5k=k/2
c=0,(3)k=k/3
d=0,(6)k=2k/3
3a-c+d-b=13
3*k/5-k/3+2k/3-k/2=13
3*k/5+k/3-k/2=13
18k+10k-15k=390
13k=390
k=30
a=k/5=30/5=6
b=k/2=30/2=15
c=k/3=30/3=10
d=2k/3=2*30/3=20