Question

Determinati numerele a,b,c ,stiind ca a<b<c si ca 9×a+9×b+9×c=72

Answer 1

a < b < c

9 × a + 9 × b + 9 × c = 72

9 × ( a + b + c ) = 72

a + b + c = 72 : 9

a + b + c = 8

a < b < c

a = 1 ; b = 2 ; c = 5

a = 1 ; b = 3 ; c = 4

Succes !!