Question

determinati numerele a si b stiind ca sint invers proportionale cu 2 si 3 iar a-b =12

Answer 1

a·2=b·3=k
⇒a·2=k⇒a=k/2;
⇒b·3=k⇒b=k/3;
a-b=12
⇒k/2-k/3=12
⇒3k/6-2k/6=12
⇒k/6=12
⇒k=6·12⇒k=72;
⇒a=k/2⇒a=72/2⇒a=36;
⇒b=k/3⇒b=72/3⇒b=24;

Answer 2

ax2=bx3 --->ax2=k--->a=k/2
              --->bx3=k--->b=k/3
a-b=12
--->k/2-k/3=12
---->3k/6-2k/6=12
--->k/6=12
--->k=6x12
--->k=72
--->a=k/2--->a=72/2--->a=36
--->b=k/3--->b=72/3--->b=24
proba:a-b=12--->36-24=12

--->-inseamna ,,reulta''