Question

Determinati numerele abc stiind ca:
abc=ab×cb+c

Answer 1

abc=ab•cb+c

ab0+c=ab•cb+c

=> ab0=ab•cb

sau ab•10=ab•cb

=> cb=10, deci c=1; b=0; a∈{1,2,3,......., 9}

abc∈{101,201,301,401,.....,901}